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2/x+3/2x-1/2=2/3
We move all terms to the left:
2/x+3/2x-1/2-(2/3)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
2/x+3/2x-1/2-(+2/3)=0
We get rid of parentheses
2/x+3/2x-1/2-2/3=0
We calculate fractions
(-16x^2)/24x^2+48x/24x^2+27x/24x^2+(-9x)/24x^2=0
We multiply all the terms by the denominator
(-16x^2)+48x+27x+(-9x)=0
We add all the numbers together, and all the variables
(-16x^2)+75x+(-9x)=0
We get rid of parentheses
-16x^2+75x-9x=0
We add all the numbers together, and all the variables
-16x^2+66x=0
a = -16; b = 66; c = 0;
Δ = b2-4ac
Δ = 662-4·(-16)·0
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-66}{2*-16}=\frac{-132}{-32} =4+1/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+66}{2*-16}=\frac{0}{-32} =0 $
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