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2/x+3+5/x-4=35/(x+3)(x-4)
We move all terms to the left:
2/x+3+5/x-4-(35/(x+3)(x-4))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x+3)(x-4))!=0We add all the numbers together, and all the variables
x∈R
2/x+5/x-(35/(x+3)(x-4))-1=0
We multiply parentheses ..
-(35/(+x^2-4x+3x-12))+2/x+5/x-1=0
We calculate fractions
We do not support expression: x^3
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