2/x+2+4/3x

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Solution for 2/x+2+4/3x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(4/3)*x+2/x+2 = 0

4/3*x^1+2*x^-1+2*x^0 = 0

(4/3*x^2+2*x^1+2*x^0)/(x^1) = 0 // * x^2

x^1*(4/3*x^2+2*x^1+2*x^0) = 0

x^1

(4/3)*x^2+2*x+2 = 0

(4/3)*x^2+2*x+2 = 0

DELTA = 2^2-(2*4*(4/3))

DELTA = -20/3

DELTA < 0

x in { } 

x belongs to the empty set

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