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2/x+10/2x=6
We move all terms to the left:
2/x+10/2x-(6)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x!=0We calculate fractions
x!=0/2
x!=0
x∈R
4x/2x^2+10x/2x^2-6=0
We multiply all the terms by the denominator
4x+10x-6*2x^2=0
We add all the numbers together, and all the variables
14x-6*2x^2=0
Wy multiply elements
-12x^2+14x=0
a = -12; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-12)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-12}=\frac{-28}{-24} =1+1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-12}=\frac{0}{-24} =0 $
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