2/n=4/n+3

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Solution for 2/n=4/n+3 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

2/n = 4/n+3 // - 4/n+3

2/n-(4/n)-3 = 0

2/n-4*n^-1-3 = 0

-2*n^-1 = 3 // : -2

n^-1 = -3/2

-1 < 0

1/(n^1) = -3/2 // * n^1

1 = -3/2*n^1 // : -3/2

-2/3 = n^1

n = -2/3

n = -2/3

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