2/m+16=4+6/11m

Solution for 2/m+16=4+6/11m equation:

2/m+16=4+6/11m

We move all terms to the left:

2/m+16-(4+6/11m)=0


Domain of the equation: m!=0

m∈R



Domain of the equation: 11m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

2/m-(6/11m+4)+16=0

We get rid of parentheses

2/m-6/11m-4+16=0

We calculate fractions


22m/11m^2+(-6m)/11m^2-4+16=0

We add all the numbers together, and all the variables

22m/11m^2+(-6m)/11m^2+12=0

We multiply all the terms by the denominator


22m+(-6m)+12*11m^2=0

Wy multiply elements

132m^2+22m+(-6m)=0

We get rid of parentheses

132m^2+22m-6m=0

We add all the numbers together, and all the variables

132m^2+16m=0

a = 132; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·132·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*132}=\frac{-32}{264}
=-4/33
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*132}=\frac{0}{264}
=0
$