2/b-5=17/b

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Solution for 2/b-5=17/b equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

2/b-5 = 17/b // - 17/b

2/b-(17/b)-5 = 0

2/b-17*b^-1-5 = 0

-15*b^-1 = 5 // : -15

b^-1 = -1/3

-1 < 0

1/(b^1) = -1/3 // * b^1

1 = -1/3*b^1 // : -1/3

-3 = b^1

b = -3

b = -3

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