2/Z=-3/4Z-1

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Solution for 2/Z=-3/4Z-1 equation: 


D( Z )

Z = 0

Z = 0

Z = 0

Z in (-oo:0) U (0:+oo)

2/Z = (-3/4)*Z-1 // - (-3/4)*Z-1

2/Z-((-3/4)*Z)+1 = 0

(3/4)*Z+2/Z+1 = 0

3/4*Z^1+2*Z^-1+1*Z^0 = 0

(3/4*Z^2+1*Z^1+2*Z^0)/(Z^1) = 0 // * Z^2

Z^1*(3/4*Z^2+1*Z^1+2*Z^0) = 0

Z^1

(3/4)*Z^2+Z+2 = 0

(3/4)*Z^2+Z+2 = 0

DELTA = 1^2-(2*4*(3/4))

DELTA = -5

DELTA < 0

Z in { } 

Z belongs to the empty set

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