2/9x-8)+4x=6(x-2)-4

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Solution for 2/9x-8)+4x=6(x-2)-4 equation: 



2/9x-8)+4x=6(x-2)-4

We move all terms to the left:

2/9x-8)+4x-(6(x-2)-4)=0



Domain of the equation: 9x!=0

x!=0/9

x!=0

x∈R



We add all the numbers together, and all the variables

2/9x-8)+4x-(6(x-2)=0

We multiply all the terms by the denominator


4x-(6(x-2))*9x+2-8=0

We add all the numbers together, and all the variables

4x-(6(x-2))*9x-6=0

We move all terms containing x to the left, all other terms to the right

4x-(6(x-2))*9x=6

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