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2/9x+1=-2/3x-2
We move all terms to the left:
2/9x+1-(-2/3x-2)=0
Domain of the equation: 9x!=0
x!=0/9
x!=0
x∈R
Domain of the equation: 3x-2)!=0We get rid of parentheses
x∈R
2/9x+2/3x+2+1=0
We calculate fractions
6x/27x^2+18x/27x^2+2+1=0
We add all the numbers together, and all the variables
6x/27x^2+18x/27x^2+3=0
We multiply all the terms by the denominator
6x+18x+3*27x^2=0
We add all the numbers together, and all the variables
24x+3*27x^2=0
Wy multiply elements
81x^2+24x=0
a = 81; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·81·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*81}=\frac{-48}{162} =-8/27 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*81}=\frac{0}{162} =0 $
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