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2/9x+1/2x=2
We move all terms to the left:
2/9x+1/2x-(2)=0
Domain of the equation: 9x!=0
x!=0/9
x!=0
x∈R
Domain of the equation: 2x!=0We calculate fractions
x!=0/2
x!=0
x∈R
4x/18x^2+9x/18x^2-2=0
We multiply all the terms by the denominator
4x+9x-2*18x^2=0
We add all the numbers together, and all the variables
13x-2*18x^2=0
Wy multiply elements
-36x^2+13x=0
a = -36; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·(-36)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*-36}=\frac{-26}{-72} =13/36 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*-36}=\frac{0}{-72} =0 $
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