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2/9(u+3)=8/9-u
We move all terms to the left:
2/9(u+3)-(8/9-u)=0
Domain of the equation: 9(u+3)!=0
u∈R
Domain of the equation: 9-u)!=0We add all the numbers together, and all the variables
We move all terms containing u to the left, all other terms to the right
-u)!=-9
u!=-9/1
u!=-9
u∈R
2/9(u+3)-(-1u+8/9)=0
We get rid of parentheses
2/9(u+3)+1u-8/9=0
We calculate fractions
u=0
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