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2/9(3x-4)=1/3(10x-6)
We move all terms to the left:
2/9(3x-4)-(1/3(10x-6))=0
Domain of the equation: 9(3x-4)!=0
x∈R
Domain of the equation: 3(10x-6))!=0We calculate fractions
x∈R
(6x1/(9(3x-4)*3(10x-6)))+(-9x3/(9(3x-4)*3(10x-6)))=0
We calculate terms in parentheses: +(6x1/(9(3x-4)*3(10x-6))), so:
6x1/(9(3x-4)*3(10x-6))
We multiply all the terms by the denominator
6x1
We add all the numbers together, and all the variables
6x
Back to the equation:
+(6x)
We calculate terms in parentheses: +(-9x3/(9(3x-4)*3(10x-6))), so:
-9x3/(9(3x-4)*3(10x-6))
We multiply all the terms by the denominator
-9x3
We add all the numbers together, and all the variables
-9x^3
We do not support expression: x^3
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