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2/9(2x-14x+3x)=7/11(2x-5x-5x+9)
We move all terms to the left:
2/9(2x-14x+3x)-(7/11(2x-5x-5x+9))=0
Domain of the equation: 9(2x-14x+3x)!=0
x∈R
Domain of the equation: 11(2x-5x-5x+9))!=0We add all the numbers together, and all the variables
x∈R
2/9(-9x)-(7/11(-8x+9))=0
We calculate fractions
(22x(-)/(9(-9x)*11(-8x+9)))+(-63x0/(9(-9x)*11(-8x+9)))=0
We calculate terms in parentheses: +(22x(-)/(9(-9x)*11(-8x+9))), so:
22x(-)/(9(-9x)*11(-8x+9))
We add all the numbers together, and all the variables
22x0/(9(-9x)*11(-8x+9))
We multiply all the terms by the denominator
22x0
We add all the numbers together, and all the variables
22x
Back to the equation:
+(22x)
We calculate terms in parentheses: +(-63x0/(9(-9x)*11(-8x+9))), so:We get rid of parentheses
-63x0/(9(-9x)*11(-8x+9))
We multiply all the terms by the denominator
-63x0
We add all the numbers together, and all the variables
-63x
Back to the equation:
+(-63x)
22x-63x=0
We add all the numbers together, and all the variables
-41x=0
x=0/-41
x=0
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