2/9(18a+2)=1/2(4a-20)

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Solution for 2/9(18a+2)=1/2(4a-20) equation: 



2/9(18a+2)=1/2(4a-20)

We move all terms to the left:

2/9(18a+2)-(1/2(4a-20))=0



Domain of the equation: 9(18a+2)!=0

a∈R





Domain of the equation: 2(4a-20))!=0

a∈R



We calculate fractions


(4a4/(9(18a+2)*2(4a-20)))+(-9a1/(9(18a+2)*2(4a-20)))=0



We calculate terms in parentheses: +(4a4/(9(18a+2)*2(4a-20))), so:

4a4/(9(18a+2)*2(4a-20))

We multiply all the terms by the denominator


4a4

We add all the numbers together, and all the variables

4a^4

We do not support eapression: a^4

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