2/8=(n+4)/(n-4)

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Solution for 2/8=(n+4)/(n-4) equation: 


D( n )

n-4 = 0

n-4 = 0

n-4 = 0

n-4 = 0 // + 4

n = 4

n in (-oo:4) U (4:+oo)

2/8 = (n+4)/(n-4) // - (n+4)/(n-4)

2/8-((n+4)/(n-4)) = 0

(-1*(n+4))/(n-4)+1/4 = 0

(-1*4*(n+4))/(4*(n-4))+(1*(n-4))/(4*(n-4)) = 0

1*(n-4)-1*4*(n+4) = 0

-3*n-20 = 0

(-3*n-20)/(4*(n-4)) = 0

(-3*n-20)/(4*(n-4)) = 0 // * 4*(n-4)

-3*n-20 = 0

-3*n-20 = 0 // + 20

-3*n = 20 // : -3

n = 20/(-3)

n = -20/3

n = -20/3

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