2/7x+8=1/2x+18

Solution for 2/7x+8=1/2x+18 equation:

2/7x+8=1/2x+18

We move all terms to the left:

2/7x+8-(1/2x+18)=0


Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



Domain of the equation: 2x+18)!=0

x∈R


We get rid of parentheses

2/7x-1/2x-18+8=0

We calculate fractions


4x/14x^2+(-7x)/14x^2-18+8=0

We add all the numbers together, and all the variables

4x/14x^2+(-7x)/14x^2-10=0

We multiply all the terms by the denominator


4x+(-7x)-10*14x^2=0

Wy multiply elements

-140x^2+4x+(-7x)=0

We get rid of parentheses

-140x^2+4x-7x=0

We add all the numbers together, and all the variables

-140x^2-3x=0

a = -140; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-140)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-140}=\frac{0}{-280}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-140}=\frac{6}{-280}
=-3/140
$