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2/7x+1=x
We move all terms to the left:
2/7x+1-(x)=0
Domain of the equation: 7x!=0We add all the numbers together, and all the variables
x!=0/7
x!=0
x∈R
-1x+2/7x+1=0
We multiply all the terms by the denominator
-1x*7x+1*7x+2=0
Wy multiply elements
-7x^2+7x+2=0
a = -7; b = 7; c = +2;
Δ = b2-4ac
Δ = 72-4·(-7)·2
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{105}}{2*-7}=\frac{-7-\sqrt{105}}{-14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{105}}{2*-7}=\frac{-7+\sqrt{105}}{-14} $
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