2/7t+1=3/11t-11

Solution for 2/7t+1=3/11t-11 equation:

2/7t+1=3/11t-11

We move all terms to the left:

2/7t+1-(3/11t-11)=0


Domain of the equation: 7t!=0

t!=0/7

t!=0

t∈R



Domain of the equation: 11t-11)!=0

t∈R


We get rid of parentheses

2/7t-3/11t+11+1=0

We calculate fractions


22t/77t^2+(-21t)/77t^2+11+1=0

We add all the numbers together, and all the variables

22t/77t^2+(-21t)/77t^2+12=0

We multiply all the terms by the denominator


22t+(-21t)+12*77t^2=0

Wy multiply elements

924t^2+22t+(-21t)=0

We get rid of parentheses

924t^2+22t-21t=0

We add all the numbers together, and all the variables

924t^2+t=0

a = 924; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·924·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*924}=\frac{-2}{1848}
=-1/924
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*924}=\frac{0}{1848}
=0
$