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2/7p+5=1/3p
We move all terms to the left:
2/7p+5-(1/3p)=0
Domain of the equation: 7p!=0
p!=0/7
p!=0
p∈R
Domain of the equation: 3p)!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
2/7p-(+1/3p)+5=0
We get rid of parentheses
2/7p-1/3p+5=0
We calculate fractions
6p/21p^2+(-7p)/21p^2+5=0
We multiply all the terms by the denominator
6p+(-7p)+5*21p^2=0
Wy multiply elements
105p^2+6p+(-7p)=0
We get rid of parentheses
105p^2+6p-7p=0
We add all the numbers together, and all the variables
105p^2-1p=0
a = 105; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·105·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*105}=\frac{0}{210} =0 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*105}=\frac{2}{210} =1/105 $
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