2/7m+3/14m=1

Solution for 2/7m+3/14m=1 equation:

2/7m+3/14m=1

We move all terms to the left:

2/7m+3/14m-(1)=0


Domain of the equation: 7m!=0

m!=0/7

m!=0

m∈R



Domain of the equation: 14m!=0

m!=0/14

m!=0

m∈R


We calculate fractions


28m/98m^2+21m/98m^2-1=0

We multiply all the terms by the denominator


28m+21m-1*98m^2=0

We add all the numbers together, and all the variables

49m-1*98m^2=0

Wy multiply elements

-98m^2+49m=0

a = -98; b = 49; c = 0;
Δ = b2-4ac
Δ = 492-4·(-98)·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-49}{2*-98}=\frac{-98}{-196}
=1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+49}{2*-98}=\frac{0}{-196}
=0
$