2/7=x-4/x-3

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Solution for 2/7=x-4/x-3 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2/7 = x-(4/x)-3 // - x-(4/x)-3

4/x-x+2/7+3 = 0

4*x^-1-1*x^1+23/7*x^0 = 0

(23/7*x^1-1*x^2+4*x^0)/(x^1) = 0 // * x^2

x^1*(23/7*x^1-1*x^2+4*x^0) = 0

x^1

(23/7)*x-x^2+4 = 0

(23/7)*x-x^2+4 = 0

DELTA = (23/7)^2-(-1*4*4)

DELTA = 1313/49

DELTA > 0

x = ((1313/49)^(1/2)-(23/7))/(-1*2) or x = (-(23/7)-(1313/49)^(1/2))/(-1*2)

x = ((1313/49)^(1/2)-23/7)/(-2) or x = ((1313/49)^(1/2)+23/7)/2

x in { ((1313/49)^(1/2)-23/7)/(-2), ((1313/49)^(1/2)+23/7)/2}

x in { ((1313/49)^(1/2)-23/7)/(-2), ((1313/49)^(1/2)+23/7)/2 }

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