2/7(4+c)=16

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Solution for 2/7(4+c)=16 equation: 



2/7(4+c)=16

We move all terms to the left:

2/7(4+c)-(16)=0



Domain of the equation: 7(4+c)!=0

c∈R



We add all the numbers together, and all the variables

2/7(c+4)-16=0

We multiply all the terms by the denominator


-16*7(c+4)+2=0

Wy multiply elements

-112c(c+2=0

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