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2/7(3x-2)=1/5(-5x-4)
We move all terms to the left:
2/7(3x-2)-(1/5(-5x-4))=0
Domain of the equation: 7(3x-2)!=0
x∈R
Domain of the equation: 5(-5x-4))!=0We calculate fractions
x∈R
(10x(-)/(7(3x-2)*5(-5x-4)))+(-7x3/(7(3x-2)*5(-5x-4)))=0
We calculate terms in parentheses: +(10x(-)/(7(3x-2)*5(-5x-4))), so:
10x(-)/(7(3x-2)*5(-5x-4))
We add all the numbers together, and all the variables
10x0/(7(3x-2)*5(-5x-4))
We multiply all the terms by the denominator
10x0
We add all the numbers together, and all the variables
10x
Back to the equation:
+(10x)
We calculate terms in parentheses: +(-7x3/(7(3x-2)*5(-5x-4))), so:
-7x3/(7(3x-2)*5(-5x-4))
We multiply all the terms by the denominator
-7x3
We add all the numbers together, and all the variables
-7x^3
We do not support expression: x^3
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