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2/6x-x=2
We move all terms to the left:
2/6x-x-(2)=0
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
-1x+2/6x-2=0
We multiply all the terms by the denominator
-1x*6x-2*6x+2=0
Wy multiply elements
-6x^2-12x+2=0
a = -6; b = -12; c = +2;
Δ = b2-4ac
Δ = -122-4·(-6)·2
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-8\sqrt{3}}{2*-6}=\frac{12-8\sqrt{3}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+8\sqrt{3}}{2*-6}=\frac{12+8\sqrt{3}}{-12} $
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