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2/6v-1/7v+14=20
We move all terms to the left:
2/6v-1/7v+14-(20)=0
Domain of the equation: 6v!=0
v!=0/6
v!=0
v∈R
Domain of the equation: 7v!=0We add all the numbers together, and all the variables
v!=0/7
v!=0
v∈R
2/6v-1/7v-6=0
We calculate fractions
14v/42v^2+(-6v)/42v^2-6=0
We multiply all the terms by the denominator
14v+(-6v)-6*42v^2=0
Wy multiply elements
-252v^2+14v+(-6v)=0
We get rid of parentheses
-252v^2+14v-6v=0
We add all the numbers together, and all the variables
-252v^2+8v=0
a = -252; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-252)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-252}=\frac{-16}{-504} =2/63 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-252}=\frac{0}{-504} =0 $
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