2/5z=7

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Solution for 2/5z=7 equation: 



2/5z=7

We move all terms to the left:

2/5z-(7)=0



Domain of the equation: 5z!=0

z!=0/5

z!=0

z∈R



We multiply all the terms by the denominator


-7*5z+2=0

Wy multiply elements

-35z+2=0

We move all terms containing z to the left, all other terms to the right

-35z=-2

z=-2/-35

z=2/35

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