2/5y=35

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Solution for 2/5y=35 equation: 



2/5y=35

We move all terms to the left:

2/5y-(35)=0



Domain of the equation: 5y!=0

y!=0/5

y!=0

y∈R



We multiply all the terms by the denominator


-35*5y+2=0

Wy multiply elements

-175y+2=0

We move all terms containing y to the left, all other terms to the right

-175y=-2

y=-2/-175

y=2/175

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