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2/5y-8=20*3/4y
We move all terms to the left:
2/5y-8-(20*3/4y)=0
Domain of the equation: 5y!=0
y!=0/5
y!=0
y∈R
Domain of the equation: 4y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
2/5y-(+20*3/4y)-8=0
We get rid of parentheses
2/5y-20*3/4y-8=0
We calculate fractions
8y/20y^2+(-1500y)/20y^2-8=0
We multiply all the terms by the denominator
8y+(-1500y)-8*20y^2=0
Wy multiply elements
-160y^2+8y+(-1500y)=0
We get rid of parentheses
-160y^2+8y-1500y=0
We add all the numbers together, and all the variables
-160y^2-1492y=0
a = -160; b = -1492; c = 0;
Δ = b2-4ac
Δ = -14922-4·(-160)·0
Δ = 2226064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2226064}=1492$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1492)-1492}{2*-160}=\frac{0}{-320} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1492)+1492}{2*-160}=\frac{2984}{-320} =-9+13/40 $
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