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2/5y-5/8y=5/13
We move all terms to the left:
2/5y-5/8y-(5/13)=0
Domain of the equation: 5y!=0
y!=0/5
y!=0
y∈R
Domain of the equation: 8y!=0We add all the numbers together, and all the variables
y!=0/8
y!=0
y∈R
2/5y-5/8y-(+5/13)=0
We get rid of parentheses
2/5y-5/8y-5/13=0
We calculate fractions
(-1600y^2)/520y^2+208y/520y^2+(-325y)/520y^2=0
We multiply all the terms by the denominator
(-1600y^2)+208y+(-325y)=0
We get rid of parentheses
-1600y^2+208y-325y=0
We add all the numbers together, and all the variables
-1600y^2-117y=0
a = -1600; b = -117; c = 0;
Δ = b2-4ac
Δ = -1172-4·(-1600)·0
Δ = 13689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{13689}=117$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-117)-117}{2*-1600}=\frac{0}{-3200} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-117)+117}{2*-1600}=\frac{234}{-3200} =-117/1600 $
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