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2/5y+4=5/6y+2
We move all terms to the left:
2/5y+4-(5/6y+2)=0
Domain of the equation: 5y!=0
y!=0/5
y!=0
y∈R
Domain of the equation: 6y+2)!=0We get rid of parentheses
y∈R
2/5y-5/6y-2+4=0
We calculate fractions
12y/30y^2+(-25y)/30y^2-2+4=0
We add all the numbers together, and all the variables
12y/30y^2+(-25y)/30y^2+2=0
We multiply all the terms by the denominator
12y+(-25y)+2*30y^2=0
Wy multiply elements
60y^2+12y+(-25y)=0
We get rid of parentheses
60y^2+12y-25y=0
We add all the numbers together, and all the variables
60y^2-13y=0
a = 60; b = -13; c = 0;
Δ = b2-4ac
Δ = -132-4·60·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-13}{2*60}=\frac{0}{120} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+13}{2*60}=\frac{26}{120} =13/60 $
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