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2/5x=x-16
We move all terms to the left:
2/5x-(x-16)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
2/5x-x+16=0
We multiply all the terms by the denominator
-x*5x+16*5x+2=0
Wy multiply elements
-5x^2+80x+2=0
a = -5; b = 80; c = +2;
Δ = b2-4ac
Δ = 802-4·(-5)·2
Δ = 6440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6440}=\sqrt{4*1610}=\sqrt{4}*\sqrt{1610}=2\sqrt{1610}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-2\sqrt{1610}}{2*-5}=\frac{-80-2\sqrt{1610}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+2\sqrt{1610}}{2*-5}=\frac{-80+2\sqrt{1610}}{-10} $
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