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2/5x-6/x=1
We move all terms to the left:
2/5x-6/x-(1)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: x!=0We calculate fractions
x∈R
2x/5x^2+(-30x)/5x^2-1=0
We multiply all the terms by the denominator
2x+(-30x)-1*5x^2=0
Wy multiply elements
-5x^2+2x+(-30x)=0
We get rid of parentheses
-5x^2+2x-30x=0
We add all the numbers together, and all the variables
-5x^2-28x=0
a = -5; b = -28; c = 0;
Δ = b2-4ac
Δ = -282-4·(-5)·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-28}{2*-5}=\frac{0}{-10} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+28}{2*-5}=\frac{56}{-10} =-5+3/5 $
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