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2/5x-3=5/12+4x
We move all terms to the left:
2/5x-3-(5/12+4x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 12+4x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
4x)!=-12
x!=-12/1
x!=-12
x∈R
2/5x-(+4x+5/12)-3=0
We get rid of parentheses
2/5x-4x-3-5/12=0
We calculate fractions
There is no solution for this equation
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