2/5x-(x+1/2)=1/10(x+1)

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Solution for 2/5x-(x+1/2)=1/10(x+1) equation: 


x in (-oo:+oo)

(2/5)*x-x-(1/2) = (1/10)*(x+1) // - (1/10)*(x+1)

(2/5)*x-((1/10)*(x+1))-x-(1/2) = 0

(-1/10)*(x+1)+(2/5)*x-x-1/2 = 0

(2*x)/5-1/10*(x+1)-x-1/2 = 0

(-1/10*2*5*(x+1))/(2*5)+(2*2*x)/(2*5)+(2*5*(-x))/(2*5)+(-1*5)/(2*5) = 0

2*2*x-1/10*2*5*(x+1)+2*5*(-x)-1*5 = 0

3*x-10*x-5-1 = 0

-7*x-5-1 = 0

-7*x-6 = 0

(-7*x-6)/(2*5) = 0

(-7*x-6)/(2*5) = 0 // * 2*5

-7*x-6 = 0

-7*x-6 = 0 // + 6

-7*x = 6 // : -7

x = 6/(-7)

x = -6/7

x = -6/7

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