2/5x+4=1/4x

Solution for 2/5x+4=1/4x equation:

2/5x+4=1/4x

We move all terms to the left:

2/5x+4-(1/4x)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2/5x-(+1/4x)+4=0

We get rid of parentheses

2/5x-1/4x+4=0

We calculate fractions


8x/20x^2+(-5x)/20x^2+4=0

We multiply all the terms by the denominator


8x+(-5x)+4*20x^2=0

Wy multiply elements

80x^2+8x+(-5x)=0

We get rid of parentheses

80x^2+8x-5x=0

We add all the numbers together, and all the variables

80x^2+3x=0

a = 80; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·80·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*80}=\frac{-6}{160}
=-3/80
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*80}=\frac{0}{160}
=0
$