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2/5x+3/4x=360
We move all terms to the left:
2/5x+3/4x-(360)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 4x!=0We calculate fractions
x!=0/4
x!=0
x∈R
8x/20x^2+15x/20x^2-360=0
We multiply all the terms by the denominator
8x+15x-360*20x^2=0
We add all the numbers together, and all the variables
23x-360*20x^2=0
Wy multiply elements
-7200x^2+23x=0
a = -7200; b = 23; c = 0;
Δ = b2-4ac
Δ = 232-4·(-7200)·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-23}{2*-7200}=\frac{-46}{-14400} =23/7200 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+23}{2*-7200}=\frac{0}{-14400} =0 $
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