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2/5x+2x=180
We move all terms to the left:
2/5x+2x-(180)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
2x+2/5x-180=0
We multiply all the terms by the denominator
2x*5x-180*5x+2=0
Wy multiply elements
10x^2-900x+2=0
a = 10; b = -900; c = +2;
Δ = b2-4ac
Δ = -9002-4·10·2
Δ = 809920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{809920}=\sqrt{64*12655}=\sqrt{64}*\sqrt{12655}=8\sqrt{12655}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-900)-8\sqrt{12655}}{2*10}=\frac{900-8\sqrt{12655}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-900)+8\sqrt{12655}}{2*10}=\frac{900+8\sqrt{12655}}{20} $
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