2/5x+12=2/4x+7

Solution for 2/5x+12=2/4x+7 equation:

2/5x+12=2/4x+7

We move all terms to the left:

2/5x+12-(2/4x+7)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 4x+7)!=0

x∈R


We get rid of parentheses

2/5x-2/4x-7+12=0

We calculate fractions


8x/20x^2+(-10x)/20x^2-7+12=0

We add all the numbers together, and all the variables

8x/20x^2+(-10x)/20x^2+5=0

We multiply all the terms by the denominator


8x+(-10x)+5*20x^2=0

Wy multiply elements

100x^2+8x+(-10x)=0

We get rid of parentheses

100x^2+8x-10x=0

We add all the numbers together, and all the variables

100x^2-2x=0

a = 100; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·100·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*100}=\frac{0}{200}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*100}=\frac{4}{200}
=1/50
$