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2/5n+8=1/2n+2
We move all terms to the left:
2/5n+8-(1/2n+2)=0
Domain of the equation: 5n!=0
n!=0/5
n!=0
n∈R
Domain of the equation: 2n+2)!=0We get rid of parentheses
n∈R
2/5n-1/2n-2+8=0
We calculate fractions
4n/10n^2+(-5n)/10n^2-2+8=0
We add all the numbers together, and all the variables
4n/10n^2+(-5n)/10n^2+6=0
We multiply all the terms by the denominator
4n+(-5n)+6*10n^2=0
Wy multiply elements
60n^2+4n+(-5n)=0
We get rid of parentheses
60n^2+4n-5n=0
We add all the numbers together, and all the variables
60n^2-1n=0
a = 60; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·60·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*60}=\frac{0}{120} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*60}=\frac{2}{120} =1/60 $
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