2/5m=27

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Solution for 2/5m=27 equation: 



2/5m=27

We move all terms to the left:

2/5m-(27)=0



Domain of the equation: 5m!=0

m!=0/5

m!=0

m∈R



We multiply all the terms by the denominator


-27*5m+2=0

Wy multiply elements

-135m+2=0

We move all terms containing m to the left, all other terms to the right

-135m=-2

m=-2/-135

m=2/135

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