2/5k-7=41

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Solution for 2/5k-7=41 equation: 



2/5k-7=41

We move all terms to the left:

2/5k-7-(41)=0



Domain of the equation: 5k!=0

k!=0/5

k!=0

k∈R



We add all the numbers together, and all the variables

2/5k-48=0

We multiply all the terms by the denominator


-48*5k+2=0

Wy multiply elements

-240k+2=0

We move all terms containing k to the left, all other terms to the right

-240k=-2

k=-2/-240

k=1/120

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