2/5k+2/3=32/3k=

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Solution for 2/5k+2/3=32/3k= equation: 



2/5k+2/3=32/3k=

We move all terms to the left:

2/5k+2/3-(32/3k)=0



Domain of the equation: 5k!=0

k!=0/5

k!=0

k∈R





Domain of the equation: 3k)!=0

k!=0/1

k!=0

k∈R



We add all the numbers together, and all the variables

2/5k-(+32/3k)+2/3=0

We get rid of parentheses

2/5k-32/3k+2/3=0

We calculate fractions


54k/135k^2+(-160k)/135k^2+10k/135k^2=0

We multiply all the terms by the denominator


54k+(-160k)+10k=0

We add all the numbers together, and all the variables

64k+(-160k)=0

We get rid of parentheses

64k-160k=0

We add all the numbers together, and all the variables

-96k=0

k=0/-96

k=0

Równanie nie ma rozwiązania

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