2/5f=20

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Solution for 2/5f=20 equation: 



2/5f=20

We move all terms to the left:

2/5f-(20)=0



Domain of the equation: 5f!=0

f!=0/5

f!=0

f∈R



We multiply all the terms by the denominator


-20*5f+2=0

Wy multiply elements

-100f+2=0

We move all terms containing f to the left, all other terms to the right

-100f=-2

f=-2/-100

f=1/50

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