2/5f=10

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Solution for 2/5f=10 equation: 



2/5f=10

We move all terms to the left:

2/5f-(10)=0



Domain of the equation: 5f!=0

f!=0/5

f!=0

f∈R



We multiply all the terms by the denominator


-10*5f+2=0

Wy multiply elements

-50f+2=0

We move all terms containing f to the left, all other terms to the right

-50f=-2

f=-2/-50

f=1/25

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