2/5c+4-1/3c=-9

Solution for 2/5c+4-1/3c=-9 equation:

2/5c+4-1/3c=-9

We move all terms to the left:

2/5c+4-1/3c-(-9)=0


Domain of the equation: 5c!=0

c!=0/5

c!=0

c∈R



Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R


We add all the numbers together, and all the variables

2/5c-1/3c+13=0

We calculate fractions


6c/15c^2+(-5c)/15c^2+13=0

We multiply all the terms by the denominator


6c+(-5c)+13*15c^2=0

Wy multiply elements

195c^2+6c+(-5c)=0

We get rid of parentheses

195c^2+6c-5c=0

We add all the numbers together, and all the variables

195c^2+c=0

a = 195; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·195·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*195}=\frac{-2}{390}
=-1/195
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*195}=\frac{0}{390}
=0
$