2/5b=40

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Solution for 2/5b=40 equation: 



2/5b=40

We move all terms to the left:

2/5b-(40)=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



We multiply all the terms by the denominator


-40*5b+2=0

Wy multiply elements

-200b+2=0

We move all terms containing b to the left, all other terms to the right

-200b=-2

b=-2/-200

b=1/100

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