2/5=h-27/h

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Solution for 2/5=h-27/h equation:


D( h )

h = 0

h = 0

h = 0

h in (-oo:0) U (0:+oo)

2/5 = h-(27/h) // - h-(27/h)

27/h-h+2/5 = 0

27*h^-1-1*h^1+2/5*h^0 = 0

(2/5*h^1-1*h^2+27*h^0)/(h^1) = 0 // * h^2

h^1*(2/5*h^1-1*h^2+27*h^0) = 0

h^1

(2/5)*h-h^2+27 = 0

(2/5)*h-h^2+27 = 0

DELTA = (2/5)^2-(-1*4*27)

DELTA = 2704/25

DELTA > 0

h = ((2704/25)^(1/2)-(2/5))/(-1*2) or h = (-(2/5)-(2704/25)^(1/2))/(-1*2)

h = -5 or h = 27/5

h in { -5, 27/5}

h in { -5, 27/5 }

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