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2/5=4/5f
We move all terms to the left:
2/5-(4/5f)=0
Domain of the equation: 5f)!=0We add all the numbers together, and all the variables
f!=0/1
f!=0
f∈R
-(+4/5f)+2/5=0
We get rid of parentheses
-4/5f+2/5=0
We calculate fractions
=0
f=0/1
f=0
Równanie nie ma rozwiązania
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