2/5-47x=4/5+19x

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Solution for 2/5-47x=4/5+19x equation: 



2/5-47x=4/5+19x

We move all terms to the left:

2/5-47x-(4/5+19x)=0



Domain of the equation: 5+19x)!=0

We move all terms containing x to the left, all other terms to the right

19x)!=-5

x!=-5/1

x!=-5

x∈R



We add all the numbers together, and all the variables

-47x-(+19x+4/5)+2/5=0

We get rid of parentheses

-47x-19x-4/5+2/5=0

We multiply all the terms by the denominator


-47x*5-19x*5-4+2=0

We add all the numbers together, and all the variables

-47x*5-19x*5-2=0

Wy multiply elements

-235x-95x-2=0

We add all the numbers together, and all the variables

-330x-2=0

We move all terms containing x to the left, all other terms to the right

-330x=2

x=2/-330

x=-1/165

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